
%\documentclass{article}
\documentclass{report}
%\tracingall

%\usepackage[utf8]{inputenc}

\usepackage[cp1250]{inputenc}
\usepackage{polski}
\usepackage{amsmath}
\usepackage{amssymb}


\begin{document}

%\show\int

\[
\sum_{n=1}^\infty\frac1{n^2}
=\frac{\pi^2}6  
\]

\(
\sum_{n=1}^\infty\frac1{n^2}
=\frac{\pi^2}6
\)



\[
\left(
\begin{array}{cccc}
a_{11}&a_{12}&\ldots&a_{1n}\\
a_{21}&a_{22}&\cdots&a_{2n}\\
\vdots&\vdots&\ddots&\vdots\\
a_{m1}&a_{m2}&\ldots&a_{mn}
\end{array}
\right)
\]


lcr itd.
\def\1{\frac13,\frac12}

$\1$ 



$
\left(\1\right),\
\left(\1\right],\quad
\left]\1\right[,\qquad
\left\langle\1\right.;\
\left.\1\right.
$

f{}i fizyka, f l flaki

$Uff, jak brzydko! Flaki z olejem$

$\mathrm{Uff, jak brzydko! Flaki z olejem}$

$\textrm{Uff, jak brzydko! Flaki z olejem}$



\[
|x|=\left\{
\begin{array}{rl}
x,&\mbox{gdy $x\geq0$}, \\
-x,&\mbox{gdy $x<0$}.
\end{array}
\right.
\]



\def\wek#1#2{\vec{#1}=({#1}_1,{#1}_2,\ldots,{#1}_{#2})}

$\wek{x}{n}$, $\wek{y}{k}$.

$\wek{x}{12}$


\bigskip

%nie $3^3^3$
${3^3}^3$ vs. $3^{3^3}$

${a^b}^c=a^{bc}$



\vspace{12pt}

${\scriptscriptstyle3}^{\scriptstyle3^{\textstyle3}}$

$\left(\1\right),\
\displaystyle
\left(\1\right)$ $1/3$
********f
$**$ vs. $***$

$-1$, $2-1$

$*{*}*$


\def\Int{\int}
\def\Int{\int\limits}



$$
\Int_{-\infty}^{\infty}e^{-x^2}\,dx=\sqrt{\pi}
$$

Jak robiono dawniej\dots

%\the\arraycolsep
{\arraycolsep2.5pt
%\the\arraycolsep
%\begin{eqnarray*}
\begin{eqnarray}
\left(\;
\Int_{-\infty}^{\infty}e^{-x^2}\,dx
\right)^2
&=&
%\left(
\bigl(\Bigl(\biggl(\Biggl(
\Int_{-\infty}^{\infty}e^{-x^2}\,dx
\bigr)\Bigr)\biggr)\Biggr)
%\right)
\cdot
%\left(
\Biggl(\;
\Int_{-\infty}^{\infty}
e^{-y^2}\,dy
%\right)
\Biggr)
=\\
&=&
\Int
\!\!\!
\Int_{\!\!\!
\mathbf{R}^2}
e^{-(x^2+y^2)}\,dx\,dy
={}
\nonumber
\\
%\end{eqnarray*}
\end{eqnarray}
}
%\the\arraycolsep

A jak robimy dziś


\begin{align}
\left(%\;
\Int_{-\infty}^{\infty}e^{-x^2}\,dx
\right)^2
&=
%\left(
\bigl(\Bigl(\biggl(\Biggl(
\Int_{-\infty}^{\infty}e^{-x^2}\,dx
\bigr)\Bigr)\biggr)\Biggr)
%\right)
\cdot
%\left(
\Biggl(\,
\Int_{-\infty}^{\infty}
e^{-y^2}\,dy
%\right)
\Biggr)
=\\
&=
%\Int
%\!\!\!
%\Int_{\!\!\!\mathbf{R}^2}
\iint_{\!\!\!
\mathbb{R}^2}\limits
e^{-(x^2+y^2)}\,dx\,dy
={}
%\nonumber
\notag
\\
%\end{eqnarray*}
\end{align}


AAAAA


\begin{equation}
\label{1+1}
1+1=2
\end{equation}

\prefixing
Z r/ownania \eqref{1+1} na stronie \pageref{1+1} wynika, /ze
\begin{equation}
2+1=3,
\end{equation}
ale nie
\begin{equation}
1//2+1//3=5//6.
\end{equation}
Jeszcze raz
\nonprefixing
\begin{equation}
1/2+1/3=5/6.
\end{equation}


\begin{enumerate}
\item Poziom 1.
\begin{enumerate}
\item Poziom 2.
\begin{enumerate}
\item Poziom 3.
\begin{enumerate}
\item Poziom 4.
\end{enumerate}
\end{enumerate}
\end{enumerate}
\end{enumerate}

%\prefixing
Z r/ownania (\ref{nowy}) na stronie \pageref{nowy} wynika, /ze

%{itemize}, {description}

\chapter{Rozdzia/l}

\section{Pierwsza}

\begin{equation}
\label{nowy}
2+2=4
\end{equation}
Z r/ownania \ref{1+1} na stronie \pageref{1+1} wynika, /ze


\end{document}
